Question

The 17th term of the ap exceeds its 109th term by 7.find the common difference

Answer 1

Answer:

Let a be the first term and d be the common difference of A.P. 17th term of A.P t17 = a + 16d.

10th term of A.P is t10 = a + 9d.

Given that 17th term of an A.P exceeds its 10th term by 7.

a + 16d = a + 9d + 7

7d = 7              

∴ d = 1

Answer 2

Step-by-step explanation:

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