the 19th term of an AP is equal to three times its 6th term if it's 9th term is 19 find the AP
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a19 = 3 x a6
a+18d = 3(a+5d)
a+18d = 3a +15d
3d = 2a
a = 3d/2
a9 =19
a+8d = 19
3d/2 +8d =19
19d = 19 x 2
d = 2
therefore , a = 3d/2 = 3
therefore the AP -----
3 , 5 , 7 , 9 ,11. hope it helps please mark as branliest
a+18d = 3(a+5d)
a+18d = 3a +15d
3d = 2a
a = 3d/2
a9 =19
a+8d = 19
3d/2 +8d =19
19d = 19 x 2
d = 2
therefore , a = 3d/2 = 3
therefore the AP -----
3 , 5 , 7 , 9 ,11. hope it helps please mark as branliest
Aalia111:
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