The 19th term of an AP is equal to three times its sixth term. If it's 9th term is 19,
find the AP.
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18
a19 = 3 x a6
a+18d = 3(a+5d)
a+18d = 3a +15d
3d = 2a
a = 3d/2
a9 =19
a+8d = 19
3d/2 +8d =19
19d = 19 x 2
d = 2
therefore , a = 3d/2 = 3
therefore the AP -----
3 , 5 , 7 , 9 ,11...........
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a+18d = 3(a+5d)
a+18d = 3a +15d
3d = 2a
a = 3d/2
a9 =19
a+8d = 19
3d/2 +8d =19
19d = 19 x 2
d = 2
therefore , a = 3d/2 = 3
therefore the AP -----
3 , 5 , 7 , 9 ,11...........
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Answered by
6
a+18d=3(a+5d)
a+18d=3a+15d
18d-15d=3a-a
3d=2a
3/2d=a
a+8d=19
3/2d+8d=19
3d+16d=19×2
19d=38
d=2
a=3/2(2) as d=2
a=3
A.P.=3,5,7,9,11,13,.........
a+18d=3a+15d
18d-15d=3a-a
3d=2a
3/2d=a
a+8d=19
3/2d+8d=19
3d+16d=19×2
19d=38
d=2
a=3/2(2) as d=2
a=3
A.P.=3,5,7,9,11,13,.........
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