Question

The 1st and 3rd tems of an AP are 3(2)1/2 and -3/2)1/2
respectively. The 2nd term is
(a)-6(2)1/2
(b) 0
(c) 6(2)1/2. (d) -6​

Answer 1

Answer:

Step-by-step explanation:

The 2nd term of the AP is the AM of the 1st and the 3rd terms hence,

the 2nd term is :

{3/2 X 1/2 + (-3/2 X 1/2 ) }/2

that is ,

'0'