Question

the 2 digit positive number is such that the product of it's digit is 6.If 9 is added to the number,the digit interchange their places.Find the number​

Answer 1

Answer:

here your answer...

23.

Step-by-step explanation:

let the tenth digit be x

and

the ones digit be y

the number becomes 10x+y

so

given

xy=6

y=6/x............(R)

according to question

10x+y+9=10y+x

9x-9y=-9

x-y=-1........(1)

substitute y value in equation (1)

x-6/x=-1

x^2-6=-x

x^2+x-6=0

x^2+3x-2x-6=0

x(x+3)-2(x+3)=0

(x+3)(x-2)=0

so x =2 or -3

( negative value not considered)

x=2

substitute x value in equation (R)

y=6/2=3

y=3

there for the number is 23.