Question

The 24th one please solve this i will give you 90 points for this

Answer 1

Lenght of field = 70 m

Breadth of field = 40 m

Length of pit = 10 m

Breadth of pit = 8 m

Height of pit = 5 m

Volume of earth taken out = volume of pit.

= 10 ☓ 8 ☓ 5 = 400 m^3

Now area of field = 70 ☓ 40 = 2800 m^2.

Area of base of pit = 10 ☓ 8 m^2 = 80 m^2.

Area of remaining field = 2800 - 80 2720= m^2.

Now height of field to which it rises = 400/2720 m = 0.147m = 14.7 cm

Hence it will rise to 14.7c m

Answer 2

Hey mate ^_^

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Answer:
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Area of the field on which earth taken out is to be spread

$= 70 \times 40 {m}^{2} - 10 \times 8 {m}^{2}$

$= 2800 {m}^{2} - 80 {m}^{2}$

$= 2720 {m}^{2}$

Volume of the earth dug out 

$= 10 \times 8 \times 5 {m}^{3}$

$= 400 {m}^{3}$

Rise in level of the field

= Volume of the earth dugout/Area on which earth taken out is to be spread

$= \frac{400}{2720}$

$= 0.147m$

$= 14.7cm$

Therefore,

The rise in the level of the field is 14.7cm.

#Be Brainly❤️