The 24th term of an appointment is twice it's 10th term show that it's 72nd term is 4times it's 15th term
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Let the first term and the common difference be "a" and "d"
Given. T24 = 2 T10
or, a + 23d = 2(a + 9d)
= 2a + 18d
or, a = 5d ……………… (i)
Now, T34 = a + 33d
= 5d + 33d Using (i)
= 38d ............. (ii)
T72 = a + 71d
= 5d + 71d Using (i)
= 76d
= 2 x 38d
= 2 x T34 Using (ii)
Proved
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