Question

The 25th term of the A.P.5, 7, 9, 11,.. is​

Answer 1

Answer:

53 (Ans)

Step-by-step explanation:

Let t25= 25th term of the AP  

Let a= First digit

Let d (common difference) = 2nd term - 1st term = 7-5= 2

tn = a+(n-1)d       (Use this formula)

t25= 5+ (25-1)2

t25= 5+ (24)2

t25= 5+ 48

t25 = 53

Hope this is helpful:)