The 2nd and 45th term of an arithmetic progression are 10 and 96 respectively. Find the first term and the common difference and hence find the sum of the first15 terms.
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Answer:
a2=a+d
a45=a+44d
s15=15/2(2a+[n-1]d)
Step-by-step explanation:
a+44d=96
a+d =10
________
43d=86
d=2
a+d=10
a=10-2
a=8
s15=15/2[16+(14)2]
=15/2[44]
=15*22
s15=330
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