Question

The 3 consecutive odd numbers whose sum is 45.Find the numbers

Answer 1

Let the numbers be (x+1),(x+3),(x+5) respectively
Then a/q
(x+1)+(x+3)+(x+5)=45
3x+9=45
3x=36
x=12
Therefore ,first no=x+1=12+1=13
Second no=x+3=12+3=15
Third no =12+5=17
Hope this answer will help u..
Thanku

Answer 2

Let the three consecutive odd numbers be (x + 1), (x + 3), (x + 5)

Given : Sum of three consecutive odd numbers = 45

(x+1) + (x+3) + (x+5) = 45

3x + 9 = 45

3x = 45 - 9

3x = 36

x = 36/3

x = 12

three consecutive odd numbers
= (12+1), (12+3), (12+5)

= 13, 15, 17