The 3-digit number 3y1 is divisible by 9.find the value of your and the number.
Answers
Answered by
0
ATP
3y1 = divisible by 9
we know that divisibility rule for 9 is the sum of all digits.
therefore, 3+y+1= 9
4+ y =9
y = 9- 4
y= 5
3y1 = divisible by 9
we know that divisibility rule for 9 is the sum of all digits.
therefore, 3+y+1= 9
4+ y =9
y = 9- 4
y= 5
Similar questions