Question

The 3rd term of an AP is 34 and common difference is 5.find it's 10th term?​

Answer 1

Common difference (d) = 5

Third Term = 34

Also, Third term = a + 2d

Thus, a + 2d = 34

=> a + 2(5) = 34

=> a + 10 = 34

=> a = 24

Hence, Tenth term = a + 9d

= 24 + 9(5)

= 24 + 45

= 69

Thereby, 10th term of the given AP is 69.

Answer 2

d = 5

Third Term = 34 = a + 2d

a + 2d = 34

a + 2(5) = 34

a + 10 = 34

a = 24

So, Tenth term = a + 9d

= 24 + 9(5)

= 24 + 45

= 69

Therefore, 10th term of AP is 69.