Question

The 3rd term of the Arithmetic sequence
with first term 20 and tenth 47 is?

Answer 1

Answer:

20,23,26,29....

Explanation:

a=20, a10=47

a10 = a+9d      {an=a+(n-1)d}

47=20+9d

27=9d

d=3

Therefore a=20, d=3

A.P = 20, 20+3, 20+3+3 ........

= 20,23,26,29....

Hope this helps :)