Question

The 4, Hº (N2O5, g) in kJ mol-1 on the bases of the following data is :
2NO(g) + O2(g) + 2NO, (g) 4Hº=-114 kJ mol-1
4NO, (g) + O2(g) → 2N205 (g) AH° = -102.6 kJ mol-1
4. Hº (NO,g) = 90.2 kJ mol-1​

Answer 1

You have learned that chemical equations provide us with information about the types of particles that react to form products. Chemical equations also provide us with the relative number of particles and moles that react to form products. In this section you will explore the quantitative relationships that exist between the quantities of reactants and products in a balanced equation. This is known as stoichiometry.