Question

The 4 the term of g.p is 2/3 and 7 th term is 16/81.find the g.p?​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

given, g4=2/3

g+3d=2/3.....(1)eq.

, g7=16/81

g+6d=16/81.....(2)eq.

From 1 and 2 eq.

g+6d=16/81

g+3d=2/3

- - -

3d= 16/81 - 2/3

3d= -38/81

(d= -38/243)...

put the value of d in eq 1 ...

g+3×-38/243=2/3

g -38/81 = 2/3

g = 2/3+38/81

(g = 92/81)....

g1= 92/81

g2= 92/81+(-38/243)=238/243

g3= 92/81+2×(-38/243)=200/243

then required gp is 92/81,238/243,200/243,......