the 4th and 8th terms of an appointment is 24 and the sum of it's 6th and 10th term is 44 . find sum of first 10 terms of ap
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may be my answer helps you
Step-by-step explanation:
given :- sum of 4
th
and 8
th
term is 24.
a+3d+a+7d=24
2a+10d=24
a+5d=12.....(i)
sum of 6
th
and 10
th
term is 44.
a+5d+a+9d=44
12+a+9d=44......from (i)
a+9d=32
a+5d+4d=32
12+4d=32
d=5
a+25=12
a=−13
AP=−13,−8,−3,2,7,12....
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