Question

the 4th term of a GP is 2/3 and the 7th term is 16/81 . Find the gemotric series​

Answer 1

Answer:

general term = (2/3)^(n-3)  n>=1

Step-by-step explanation:

fourth term = 2/3

seventh term = 16/81 = (2^4)/(3^4)

r = 2/3

2/3 = a (2/3)^3   --- a is first term

first term = (2/3)^(-2)

second term = (2/3)^(-1)

third  term = (2/3)^(-0)

fourth term = (2/3)^(1)

fifth term = (2/3)^(2)

sixth term = (2/3)^(3)

seventh term = (2/3)^(4)