Question

The 4th term of an ap Is 0. Prove that 25th term of the AP is three times its 11th term

Answer 1

Given a4 = 0 That is (a + 3d) = 0 ⇒ a = - 3d → (1) nth term of AP is given by an = a + (n – 1)d a11 = a + 10d = – 3d + 10d = 7d [From (1)] a25 = a+ 24d = – 3d + 24d = 21d [From (1)] = 3 x 7d Hence a25 = 3 x a11

Answer 2

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