Question

The 4th term of an ap is 10 and its 11th term is one more than 3 times its 4th term

Answer 1

Answer:

first term is 1

common difference is 3

Explanation:

4th term (a+3d) = 10........eqI

and 11 th term (a+10d)= 1+3(a+3d)...........eqII

solving we get.....

a+3d=10..........eq I

a=10-3d

Putting the value of 'a' from eqI in eqII we get.....

(a+10d) = 1+ 3(a+3d)

a+10d = 1+ 3a+9d

a+10d-3a-9d = 1

-2a+1d =1

-2 (10-3d)+1d =1

-20+6d+1d =1

7d=1+20

7d =21

d=3

putting 'd' value in eq I we get

a= 10-3d

a=10-9

a=1

I hope it helped....n ueaahhh if uh r searchin' fr AP then the formulae is

a,a+d,a+2d,a+3d........

juzz put the value and uh r done