The 4th term of an ap is zero.prove that the 25th term of the ap is three times its 11th term
Answers
Answered by
8
Solution: -
4th tem= a+ 3d
=>a + 3d = 0
=>a = -3d .... (1)
a11 = a + 10d
= -3d + 10d [using 1]
=7d ..... (2)
NOW,,,a25 = a + 24d
= -3d + 24d = 21 ..... (3)
2 is 3 times of 3..
so,,it is provrd.☺
4th tem= a+ 3d
=>a + 3d = 0
=>a = -3d .... (1)
a11 = a + 10d
= -3d + 10d [using 1]
=7d ..... (2)
NOW,,,a25 = a + 24d
= -3d + 24d = 21 ..... (3)
2 is 3 times of 3..
so,,it is provrd.☺
Similar questions