The 4th term of an arithmetic sequence is 42 and 7th term is 69.find the 35th term
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Answer:
35th term is 321
Step-by-step explanation:
tn=a+(n-1)d where a is first term d is difference
given T4=42,T7=69
t4=a+(4-1)d
42=a+3d
t7=a+(7-1)d
69=a+6d
sub both eq
69-42=a+6d-a-3d
27=3d
27/3=d
d=9
sub in one equation
42=a+3(9)
42=a+27
42-27=a
a=15
Now T(35)=a+(35-1)d
=15+34×9
=15+306
=321
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