Question

The 4th term of an arithmetic sequence is 42 and 7th term is 69.find the 35th term

Answer 1

Answer:

35th term is 321

Step-by-step explanation:

tn=a+(n-1)d where a is first term d is difference

given T4=42,T7=69

t4=a+(4-1)d

42=a+3d

t7=a+(7-1)d

69=a+6d

sub both eq

69-42=a+6d-a-3d

27=3d

27/3=d

d=9

sub in one equation

42=a+3(9)

42=a+27

42-27=a

a=15

Now T(35)=a+(35-1)d

=15+34×9

=15+306

=321

Answer 2

Answer

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Step-by-step explanation:

LEAVE A LIKE AND THANKS