Question

the 5 th term of an arithemetic sequence is 21 and 9th term is 37. write the nth term of this sequence​

Answer 1

Answer:

Explanation:

Let d be the common difference, and let x be the second term. The first three terms are, in order, x−d,x,x+d.

The sum of the first three terms is (x−d)+x+(x+d)=111.

x+x+x+d−d=3x=111

x=1113=37

Now we know that the second term is 37. The fourth term is the second term plus twice the common difference: x+2d. Since the second and fourth terms are 37 and 49, respectively, we can solve for the common difference.

x+2d=37+2d=49

2d=12

d=6

The common difference is 6. The first term is x−d=37−6=31.

Answer 2

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