Question

The 5th term of an AP is 11 and its 9th term is 7 find its 16th term

Answer 1

hey.......❤

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5th term = a + d ( 5-1 )

11 = a + 4d

and 9th term = a + d ( n- 1 )

7 = a + d ( 9-1)

7 = a + 8d

substract 1 eqn from 2nd.....

11 = a + 4d
- 7 = a + 8d
4 = -4d.....

d = 4/-4

d= -1.....

so

11 = a + 4d....

11 = a + 4*-1

11 = a -4

a = 11+4

a = 15

16th term = a + d ( 16-1 )

15 -15d = 15- 15

0

so 16th term is 0.....

hope it will help you mate.... .
please mark as brainliest

Answer 2

the answer is zero......