Question

the 6 th and 10th term is of an ap are 40 and 68. Find ap
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Answer 1

Step-by-step explanation:

a6=40

=> a+5d = 40

=>a= 40-5d

a10= 68

=>a+9d = 68

putting the value of a , we get

=>40-5d + 9d = 68

=>4d = 68-40

=> d = 28/4

=> d = 7

Now a = 40-5d

=>a= 40- 5×7

=>a= 5

a1= 5

a2= a+d = 5+7 = 12

a3= a+2d= 5+2×7 = 17

So Ap : 5,12,17.........