The 6th and 17 term of AP are 19 and 41 find the 40 term
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an=a+(n-1)d
a6=a+5d=19----- eqn1
a17=a+16d=41-----eqn2
eqn2 - eqn 1
11d=22
d=2
from eqn1
a+5d=19
a+10=19
a=9
a40 =a+39d
9+78=87
40th term =87
a6=a+5d=19----- eqn1
a17=a+16d=41-----eqn2
eqn2 - eqn 1
11d=22
d=2
from eqn1
a+5d=19
a+10=19
a=9
a40 =a+39d
9+78=87
40th term =87
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