the 6th and the 17th terms of an ap are 19 and 41 respectively find the 13th term of the AP also find the sum of first 30 terms of the AP
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a+5d=19
a+16d=41
elemination method
11d=22
d=2
substitute
a+5(2)=19
a=9
9+13(3)=48
n/2(2a+(n-1)d
15(2)(9)+(29)(2)
30(9)+58
270+58
328
a+16d=41
elemination method
11d=22
d=2
substitute
a+5(2)=19
a=9
9+13(3)=48
n/2(2a+(n-1)d
15(2)(9)+(29)(2)
30(9)+58
270+58
328
ThePlusOfminus:
Wrong
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