Question

the 6th and the 17th terms of an ap are 19 and 41 respectively find the 13th term of the AP also find the sum of first 30 terms of the AP

Answer 1

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Answer 2

a+5d=19
a+16d=41
elemination method
11d=22
d=2
substitute
a+5(2)=19
a=9
9+13(3)=48
n/2(2a+(n-1)d
15(2)(9)+(29)(2)
30(9)+58
270+58
328