Question

The 6th term from the end of the AP ;5,2,-1,-4​

Answer 1

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• $L = -31$
• $D = -3$
• $n = 6$

$Ln = L - (n - 1)D$

$= -31 - (6 - 1) -3$

$= -31 - [5 × (-3)]$

$= -31 - (-15)$

$= -31 + 15$

$= -16$

Hence, 6th term from end is$-16$

Answer 2

Given:-

• Last term (l) = -4

• First term (a) = 5

To Find:-

• 6th term of the AP

Solution:-

Firstly we have to find the common difference

Common Difference = 2nd term - 1st term

→ d = 2 -5 = -3

∴ The common difference of the given AP is -3.

As we know that

6th term = a +5d

here a is the first term

Substitute the value we get

→ 6th term = 5 + 5(-3)

→ 6th term = 5 - 15 = -10

∴The 6th term of the given AP is -10