the 6th term of an AP is zero.prove that its 21st term is triple its 11th term.
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a+5d=0
a=-5d
a+10d=11th term
11th term= (-5d)+10d=5d
21term=a+20d=(-5d)+20d=15d
therefore
21st term is triple of 11th term
a=-5d
a+10d=11th term
11th term= (-5d)+10d=5d
21term=a+20d=(-5d)+20d=15d
therefore
21st term is triple of 11th term
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