the 7th and 3rd term of AP is 12 m find the 13th
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a+6d=12...............{1}
a+2d=12...............{2}
- - -
4d=0
d=0
for a, a+6×0=12
a=12
for 13th term
a+12d
12+12×0
=12 ans
a+2d=12...............{2}
- - -
4d=0
d=0
for a, a+6×0=12
a=12
for 13th term
a+12d
12+12×0
=12 ans
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