The 7th term and 17th term of an A.P. are 24 & 54 respectively find the 12th term of this A.P.
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Answer:
A7= 24
A7= a+6d
24= a+6d
A17= 54
A17 = a+16d
54= a+16d
subtract A17 from A7
We will get ..
54-24 = a+16d- a-6d
30= 10d
d = 3
24= a+6(3)
24= a+18
24-18= a
a= 6
now A12= a+11d
A12= 6+11(3)
= 6+33
= 39
Therefore the 12th term of this AP is 39
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