The 7th term of an A.P in 4 times its 2nd term and 12th term is 2 more than 3 times of its 4th term. Find the A.P.
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Answer:
The seventh term of an AP=a
7
=4(a
2
)
The twelfth term of the AP=a
12
=2+3(a
4
)
a
7
=4(a
2
)
a+6d=4(a+d)
a+6d=4a+4d
2d=3a………………….(1)
a
12
=2+3(a
4
)
a+11d=2+3(a+3d)
a+11d=2+3a+9d
2d=2a+2………………….(2)
From (1) and (2)
3a=2a+2
a=2
d=3
Therefore, the progression is: 2,5,8……
Step-by-step explanation:
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