The 7th term of an A.P. is 20 and its 13th term is 32. Find the A.P.
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The AP is 8, 10, 12, 14........
Given:
The 7th term of the Ap
The 13th term of the Ap
We can write the 7th term of the Ap:
a + 6d = 20 ----------Equation 1
We can write the 13th term of the Ap:
a + 12d = 32 -----------Equation 2
Solving both these Linear Equations by elimination method:
Subtracting both the equations we get:
a + 6d = 20
a + 12d = 32
- 6 d = - 12
d = - 12 / - 6
d = 2
Therefore, common difference of the AP is 2.
Substituting the value of d in Equation 2:
a + 12 x 2 = 32
a + 24 = 32
a = 32 - 24
a = 8
Therefore, the first term of the AP is 8
Therefore, the AP is 8, 10, 12, 14........
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