Question

the 7th term of an A.p is 32 and 13th term is 62 find the A.p

Answer 1

Here is your answer.......

a+6d=32 ---equation 1
a+12d=62---equation 2
Subtract equation 2 from 1
6d=30
d=30/6
d=5
Substitute value of days in equation 1
a+6×5=32
a=32-30
a=2
Therefore the AP is
2,7,12,......


Hope this will help you. ......

Answer 2

Here is your solution

a+6d=32, .............. (1)
a+12d=62................... (2)

on subtracting equation 1 from. ii

a+12d-a-6d=62-32
6d= 30
d=5

hence, a=2

Ap are 2,2+5,2+5+5,2+5+5+5

Ap are 2,7,12,17

hope it helps you