The 7th term of an ap is 32 and 13th term is 62 find the ap
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Answer:
A.P. is 2, 7, 12, 17
Step-by-step explanation:tn= a+ (n-1)d --------formula
t7= a+ (7-1)d
32= a+ 6d --(1)
t13= a+ (13-1)d
62 = a+ 12d -- (2)
subtract (1) from (2)
a+12d=62
- a+6d =32
6d =30
d =5
d=5 in (1)
32= a + 6x5
32= a + 30
a= 32 - 30
a=2
A.P. is 2, 7, 12, 17
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