Question

the 7th term of an ap is 32and 13th termis 62 find 25th term and pls solve

Answer 1

T7 = 32
a+6d =32-->1

T13 = 62
a+12d = 62--->2

2 - 1
a+12d=62
-a +6d= 32
6d = 30
d = 5

a+6d =32
a+30 =32
a= 2

T25 = a+24d
T25 = 2 +120
T25=122

Answer 2

a + 6d =32
a=32-6d
a+12d=62
32-6d+12d =62
6d=30
d=5
a=32-6(5)
a=2
25th term of an ap = a+24d
=2+24(5)
=122