Question

The 7th term of an AP is 4 times of 2nd term and 12th term is 2 more than 3times of its fourth term find the progression

spam
pls answer correctly ASAP​

Answer 1

since the seventh term of the A.P is 4 times of second term.

so,

    we say,   a+6d=4{a+d}

                    a+6d=4a+4d

                     2d=3a..........................................{1}

now, the twelvth term is 2 more than 3 times its fourth term,so we say,

                  a+11d=3{a+3d}+2

                 a+11d=3a+9d+2

                 2d=2a+2

                   d=a+1........................................{2}

putting the value of d in {1} we get,

      2{a+1}=3a

       2a+2=3a

     a=2

now , putting the value of a in {2}  we get,

   d=2+1=3

   d=3  

now the A.P  is

   a,a+d,a+2d,a+3d.....................

putting the obtained value of a and d, we get,

 2,5,8,11..............................

this is required A.P