Question

two cylindrical jars contains the same amount of milk .if their diameter are in the ratio 3:4.find the ratio of their height.

Answer 1

Heya!

▶Let r and R be the radii of the bases of two cylindrical jars.

▶Let h and H be the heights of the two cylindrical jars.

▶Now, 

▶Diameter of the first jar/Diameter of the second jar = 3/4

=> 2πr/2πR = 3/4

=> r/R= 3/4

▶Again, 

▶Volume of the first jar/Volume of the second jar = 1 {since same amount of the milk contain}

=> => πr2 h/πR2 H = 1

=> r2 h/R2 H = 1

=> (r2 /R2 )*(h/H) = 1

=> (3/4)2 * (h/H) = 1

=> (9/16) * (h/H) = 1

=> h/H = 1/(9/16)
$= > \frac{h}{ H } = \frac{16}{9}$

$= > \frac{H}{h} = \frac{9}{16}$

=> H/h = 9/16

=> H : h = 9 : 16

So, the ratio of their heights is 9 : 16

$= = = = = = = = =$