The 7th term of an AP is 4times it's 2th. Term and 12th term is 2 more than 3times of its 4th term find the progession
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Given a7=4(a+d)
- a+6d=4a+4d
4a-a-6d+4d=0
3a-2d=0
next we know a12=3(a+3d)+2
a+11d=3a+9d+2
2a-2d=-2
From two equation s 3a-2d=0
2a-2d=-2
We get a=2 subtitute a ineq 1 we get d=3 so the series is 2,5,8,11,14,17,20,23,26...
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