Question

The 7th term of ap is 32and 13 the term is 62 find ap

Answer 1

Given
7th term = 32
a + 6d = 32
a = 32-6d. _1

Also
13th term = 62
a + 12d = 62
32-6d+12d = 62. (from eq. 1)
d = 5

Put it in eq. 1
Hence
a = 2

Required AP is
2,7,12,17........

Answer 2

Here is your solution

a+6d=32, .............. (1)
a+12d=62................... (2)

on subtracting equation 1 from. ii

a+12d-a-6d=62-32
6d= 30
d=5

hence, a=2

Ap are 2,2+5,2+5+5,2+5+5+5

Ap are 2,7,12,17

hope it helps you