Question

The 7th term of the sequence 0.12, 0.012, 0.0012 ...... is
(A) 1.2 x 106
(B) 1.2x1
(C) 1.2x107
(D) 1.2x1​

Answer 1

1.2x106 is correct or 0.00000012

Answer 2

Answer:

c) 1.2 ×10^7

Explanation:

Number of terms =7 (Given)

Seventh term of a sequence = 0.12 (Given)

The general term of a geometric sequence has the formula as - Tn = ar`n-1

where a = 0.12 r =1/10  and n = 7

Thus, according to the formula

T7 =0.12 × 1/10^6

T7 =0.12 × 10 ^-6

Multiplying by 10 on both the sides, ie the numerator and the denominator

T7 = 1.2 ×10^7

Thus, the 7th term of the sequence 0.12, 0.012, 0.0012 1.2 ×10^7