the 7th tetm of an AP is -4 and its 13th term is -16 . find the AP
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a7=-4
a13=-16
a7=a+6d
-4=a+6d.........1 eq
a13=a+12d
-16=a+12d...... 2eq
By elimination method..
we get
d=2
put d in eq 1
a7=a+6d
-4=a+6*2
-4=a+12
-4-12=a
a=-16
hence
Ap = - 16,-14,-12......
a13=-16
a7=a+6d
-4=a+6d.........1 eq
a13=a+12d
-16=a+12d...... 2eq
By elimination method..
we get
d=2
put d in eq 1
a7=a+6d
-4=a+6*2
-4=a+12
-4-12=a
a=-16
hence
Ap = - 16,-14,-12......
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