Question

The 8 th term of an ap is 0 proove that its 38 th term is tripple its 18 th term

Answer 1

Step-by-step explanation:

T8=0

a+7d=0》 a=-7d

from rhs 》T38=3×T18

a+37d=3(a+17d)

a+37d=3a+51d

-2a=14d

a=-7d proved

Answer 2

Step-by-step explanation:

$\huge{\bold{ solution}} \\ \\ it \: is \: given \: \\ a + 7d = 0 \\ a = - 7d \\ its \: 38th \: term \: \\ a38 = a + 37d \\ putting \: a = - 7d \\ a38 = - 7d + 37d \\ a38 = 30d - (1) \\ \\ for \: 18th \: term \: \\ a18 = a + 17d \\ putting \: a = - 7d \\ a18 = - 7d + 17d \\ a18 = 10d - (2) \\ from \: (1) \: and \: (2) = \\ a38 = 3a18$