Math, asked by rebellove5818, 11 months ago

The 8 th term of an ap is 0 proove that its 38 th term is tripple its 18 th term

Answers

Answered by Ankitakashyap2005
0

Step-by-step explanation:

T8=0

a+7d=0》 a=-7d

from rhs 》T38=3×T18

a+37d=3(a+17d)

a+37d=3a+51d

-2a=14d

a=-7d proved

Answered by anshi60
10

Step-by-step explanation:

\huge{\bold{ solution}} \\  \\ it \: is \: given \:  \\  a + 7d = 0 \\ a =  - 7d \\  its \: 38th \: term \:  \\ a38 = a + 37d  \\ putting \: a =  - 7d \\ a38 =  - 7d + 37d \\ a38 = 30d - (1) \\  \\ for \: 18th \: term \:  \\ a18 = a + 17d \\ putting \: a =  - 7d \\ a18 =  - 7d + 17d \\ a18  = 10d - (2) \\ from \: (1) \: and \: (2) =  \\ a38 = 3a18 \\  \\  \\  \\

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