Question

The square of a number is 8 more than the double of that number, what is the number?

Answer 1

Hey mate

here is your answer

let the number be x

${x}^{2} = 8 + 2x \\ {x}^{2} - 2x - 8 = 0 \\ {x}^{2} - 4x + 2x - 8 = 0 \\ x(x - 4) + 2(x - 4) = 0\\ (x + 2)(x - 4) = 0 \\ \\ x = 4 \: and \: - 2$

the number is 4.

Answer 2

Answer:

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