the 8th and 15thterm of ap are31 and 45.find ap
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Given a8=31
a+7d=31 1equ.
and a15=45
a+14d=45 2equ.
on solving 1 and 2 equation by elimination method we get
7d = 14
d=2
put d in equ. 1
a + 7d =31
a+14=31
a=7
a2=a+d=9
a3=a2+d=11
therefore AP= 7,9,11...
a+7d=31 1equ.
and a15=45
a+14d=45 2equ.
on solving 1 and 2 equation by elimination method we get
7d = 14
d=2
put d in equ. 1
a + 7d =31
a+14=31
a=7
a2=a+d=9
a3=a2+d=11
therefore AP= 7,9,11...
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1
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