The 8th term and 15th terms of an ap are 5 and 33 respectively. Find its 5th term and last term.
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let the 1st term = a
common difference = d
Given that,
a 8 = 5
a+7d=5 (1)
a 15 =33
a+14d=33(2)
subtracting equation (1) from equation(2) we get,
(a+14d)-(a+7d)=33-5
a+14d-a-7d=28
14d-7d=28
7d=28
d=28/7
d=4
putting the value of "d" in equation(2) we get,
a+14d=33
a+14×4=33
a+56=33
a=33-56
a=-23
since a=-23,d=4
therefore 5th term = a+4d=-23+4×4=-23+16= -7
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