The 8th term of an ap is 0 prove that its 38th termis triple its 18th term
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a8= 0
a38 = 3(a18)
a8= a+7d=0
=> a= -7d
=> a38= a+37d
a18= a+17d
a+37d = 3(a +17d)
-7d + 37d =3(-7d+17d)
=>30d= 3(10d)
=>30d=30d
= 0
HENCE PROVED!!!!!
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