Tina's puppy ate 100 dog biscuits on the first five days since she got it. if each day her puppy had aten 6 biscuits more than the previous day, the how many biscuits had it on the first day?
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Here,Tn=100 ,n=5,d=6..
N is no. Of days..
D is common difference
Tn is total biscuits.. so by formula.Tn=a+(n-1)d
100=a+(5-1)6
100=a+(4)6
100=a+24
100-24=a
76=a
Hence, puppy ate 76 dog biscuits on first day
N is no. Of days..
D is common difference
Tn is total biscuits.. so by formula.Tn=a+(n-1)d
100=a+(5-1)6
100=a+(4)6
100=a+24
100-24=a
76=a
Hence, puppy ate 76 dog biscuits on first day
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