The 8th term of an Ap is zero . Prove that 38th term is triple of it's 18th term
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a+7d=0=> a=-7d
a+37d=3(a+17d)------> to prove
-7d+37d=30d
-7d+17d=10d
Hence a+37d=3(a+17d)
Hence 38th term is triple of its 18th term......
a+37d=3(a+17d)------> to prove
-7d+37d=30d
-7d+17d=10d
Hence a+37d=3(a+17d)
Hence 38th term is triple of its 18th term......
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