the 8th term of an ap is zero prove that its 38 term is triple of its 18th term
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given
T8=0
=> a+7d =0
=> a= -7d----------(1)
T18= a+17d
putting a=-7d
=-7d+17d
=10d-----(2)
T38 = a+37d
putting a=-7d from (1)
T38= -7d+37d
=30d
= 3(10d)
=3T8
hence proved
T8=0
=> a+7d =0
=> a= -7d----------(1)
T18= a+17d
putting a=-7d
=-7d+17d
=10d-----(2)
T38 = a+37d
putting a=-7d from (1)
T38= -7d+37d
=30d
= 3(10d)
=3T8
hence proved
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