the 8TH termof Ap is zero prov that 38term is triple of 18 term
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Given
8th term of AP = 0
To prove
a 38 = 3(a18)
Solution
a8 = a +7d
a8 = 0
Then,
a + 7d = 0
a = -7d
Now finding the value of a 38
a 38 = a +37 d
a 38 = -7d +37 d
a 38 = 30 d
Finding the value of a18
a18 = a + 17 d
a18 = -7 d + 17 d
a18 = 10d
10d × 3 = 30 d
a 18 × 3 = a38
Hence,
3 a18 = a 38
Hence proved
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